1. Design a circuit which generates the square of 3 bit BCD number.
Sol: The Square of a 3 bit BCD number is a 6 bit number. So first write the truth table.
INPUT OUTPUT
A | B | C | S6 | S5 | S4 | S3 | S2 | S1 | |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | |
0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | |
0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | |
0 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | |
1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | |
1 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | |
1 | 1 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | |
1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 1 |
By minimal expressions are given as follows (you can use K map to do this)
S1=C
S2=0
S3=BC*
S4=C (A⊕B)
S5=A (B*+C)
S6=AB
[“*” represents complement]
Using these equations logic diagrams can be drawn.
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